Predicate (1st order) Logic

It is relatively easy to check for logical consequence in proposition logic because propositional logic is not very expressive. It is desirable to have a more expressive logic in which to write the axioms and conclusions. A first weakness of propositional logic is that it does not provide variables which can be quantified over, e.g., it is not possible to represent the all men in All men are mortal by a variable which can range of the possible values of specific men. Similarly, it is not possible to claim the existence of something with a given property by representing that something by a variable, as in "There exists a prime number greater than 27". A second weakness of propositional logic is the lack of syntax for representing objects in the domain of interest; propositional logic only permits statements about the domain of interest, e.g., it is not possible to have a symbol for Socrates, rather it is possible only to make statements about Socrates. Associated with this is the absence of functional abstraction, e.g., it is not possible to refer to the brother of Socrates.

1st order logic overcomes these two weaknesses of propositional logic by providing a richer language. The cost of this increased expressivity is the loss of decidability for logical consequence. 1st order logic is semi-decidable, which means that if a formula is a logical consequence of a set of axioms, it is possible to show that it is. However, if a formula is not a logical consequence of a set of axioms, it may not be possible to show that it is not. In addition, 1st order logic requires more complex mechanisms for checking for logical consequence.


The Language of 1st order logic

A 1st order language consists of three sets of symbols: Prolog syntax is used here: variables start with upper case alphbetic, and functors and predicate symbols start with lower case alphabetic. Functors and predicate symbols are distinguished by the context, as described below. When referring directly to a functor or predicate symbol, its arity is given after a , e.g., in blah/2, blah is the functor or predicate symbol and the arity is 2.

Example
V = { V : V starts with uppercase }
F = { geoff/0, jim/0, brother_of/1 }
P = { wise/1, taller/2 }

From the components of the language, two types of expressions are built. This is in contrast to propositional logic where only propositions exist. The first type of expression is terms. Terms are used to denote (possibly arbitrary) objects in the domain of interest. Terms thus correspond roughly to data in conventional programming. Terms are defined recursively by:

Example
geoff
Person
brother_of(jim)
brother_of(brother_of(X))

Note that if there is a functor of arity greater than 0, then there is an infinite number of terms. As might be expected, ATP for 1st order logic is much easier if the number of terms is finite (in fact it reduces to ATP for propositional logic). For this reason, it is desirable to formulate ATP problems without any functors of arity greater than 0.

The second type of expression is atoms, which correspond to the propositions of propositional logic. Atoms decribe relationships between terms (objects in the domain). Atoms are defined by:

Example
wise(geoff)
taller(Person,brother_of(jim))
wise(brother_of(brother_of(X)))

If the number of terms is infinite (which occurs if there is a functor of arity greater than 0), and there is a predicate symbol of arity greater than 0, then there is an infinite number of atoms.

Connectives are used to combine atoms into the formulae of 1st order logic. The connectives include all those used in propositional logic, and two new quantifiers:

Denoting arbitary 1st order formulae by uppercase variable letters, e.g., P, 1st order formulae are defined recursively by:

The precedence order of the above operators is ∀ ∃ ~ | & => <=>, i.e., and bind most tightly, down to <=>. This precedence ordering allows some brackets to be omitted, e.g., ∀X (clever(X) => pass(X) | lazy(X)) means ∀X (clever(X) => (pass(X) | lazy(X))). Note that the ()s round the (clever(X) => pass(X) | lazy(X)) are necessary, for otherwise the quantification would apply to only the clever(X).

Example
wise(geoff)
~taller(Person,brother_of(jim))
wise(geoff) & wise(brother_of(brother_of(Person)))
~taller(Person,brother_of(jim)) | wise(brother_of(brother_of(Person)))
wise(brother_of(brother_of(Person)) =>  wise(geoff)
wise(geoff) <=>  ~taller(Person,brother_of(jim))
(wise(geoff) & wise(brother_of(brother_of(Person)))) | wise(geoff)
∀Person ~taller(Person,brother_of(jim))
∃Person wise(brother_of(brother_of(Person)) => wise(geoff)

Atoms and the negations of atoms are called literals.

Example
wise(brother_of(X))
~taller(geoff,jim)

The scope of a quantification is the formula which follows the quantification, e.g., the scope of ∃Person in
    ∃Person wise(brother_of(brother_of(Person)) => wise(geoff)
is
    wise(brother_of(brother_of(Person)).
A variable is bound if it occurs in a quantification or it is within the scope of a quantification of that variable. Otherwise a variable is free. A formulae that has no free variables is a closed formula; otherwise a formula is open.

Example
Person is bound in in the closed formula:
∀Person ~taller(Person,brother_of(jim))

Person is free in the open formula:
~taller(Person,brother_of(jim))

Person is bound and free in the open formula:
∀Person ~taller(Person,jim) | wise(Person)

Person is bound in the closed formula:
∀Person(~taller(Person,jim) | wise(Person))

For ATP open formulae are not useful, because it is not possible to interpret (in the sense of giving meaning) open formulae. In English universal quantification is usually meant if no explicit quantification is given, e.g., "Sheep are stupid" usually means "All sheep are stupid", not "There exists a sheep that is stupid".


Translation from English to 1st Order Logic

There is often a direct translation from a problem stated in a natural language to 1st order logic. In order to make such a translation, it is necessary to:

Example
There is a barbers' club that obeys the following three conditions:
  • The (only) four of the members are Guido, Lorenzo, Petrucio, and Guido's nephew.
  • If any member A has shaved any other member B - whether himself or another - then all members have shaved A.
  • Guido has shaved his nephew.
Prove Petrucio has shaved Lorenzo
V = { V : V starts with uppercase }
F = { guido/0, lorenzo/0, petrucio/0, nephew_of/1 }
P = { member/1, shaved/2, all_shaved/1 }
  • The (only) four of the members are Guido, Lorenzo, Petrucio, and Guido's nephew.

    member(guido)
    member(lorenzo)
    member(petrucio)
    member(nephew_of(guido))
    ∀M (member(M) => (M = guido | M = lorenzo | M = petrucio | M = nephew_of(guido)))

  • If any member A has shaved any other member B - whether himself or another - then all members have shaved A.

    ∀M1∀M2 ( (member(M1) & member(M2) & shaved(M1,M2)) => all_shaved(M1) )

  • Guido has shaved his nephew.

    shaved(guido,nephew_of(guido))

  • Definitions

    ∀M1 ( all_shaved(M1) <=> ( member(M1) & ∀M2 (member(M2) => shaved(M2,M1)) ) )

  • Petrucio has shaved Lorenzo.

    shaved(petrucio,lorenzo)

Example
Every student is enrolled in at least one course. Every professor teaches at least one course. Every course has at least one student enrolled. Every course has at least one professor teaching it. The coodinator of a course is a professor who is teaching it. If a student is enrolled in a course then the student is taught by every professor who teaches the course. CSC410 is a course. Michael is a student enrolled in CSC410. Victor is the coordinator of CSC410. Therefore, Michael is taught by Victor.
V = { V : V starts with uppercase }
F = { michael/0, victor/0, csc410/0, coordinator_of/1 }
P = { student/1, profesor/1, course/1, enrolled/2, teaches/2, taught_by/2 }
  • Every student is enrolled in at least one course.

    ! [S] : ( student(S) => ? [C] : ( course(C) & enrolled(S,C) ) )

  • Every professor teaches at least one course.

    ! [P] : ( professor(P) => ? [C] : ( course(C) & teaches(P,C) ) )

  • Every course has at least one student enrolled.

    ! [C] : ( course(C) => ? [S] : ( student(S) & enrolled(S,C) ) )

  • Every course has at least one professor teaching it.

    ! [C] : ( course(C) => ? [P] : ( professor(P) & teaches(P,C) ) )

  • The coodinator of a course is a professor who is teaching it.

    ! [C] : ( course(C) => ( professor(coordinator_of(C)) & teaches(coordinator_of(C),C) ) )

  • If a student is enrolled in a course then the student is taught by every professor who teaches the course.

    ! [S,C] : ( ( student(S) & course(C) & enrolled(S,C) )
             => ! [P] : ( ( professor(P) & teaches(P,C) ) => taught_by(S,P) ) )

  • CSC410 is a course.

    course(csc410)

  • Michael is a student enrolled in CSC410.

    ( student(michael) & enrolled(michael,csc410) )

  • Victor is the coordinator of CSC410.

    coordinator_of(csc410) = victor

  • Victor teaches Michael.

    taught_by(michael,victor)

For many more ideas and suggestions, see Peter Stuber's Translation Tips.


Exercises

Convert the following into 1st order logic:

Osama Bin Laden is a terrorist. If someone is a terrorist and is dangerous, then his leader is a terrorist and is dangerous. There are some terrorists who are their own leader. Dangerous people care about themselves, or about no-one (not even themselves!).

The depth and time of a SCUBA dive determine the nitrogen absorbed on the dive. If the nitrogen absorbed on a SCUBA dive is greater than the limit, then the outcome of the dive is illness. Illness is the only possible bad outcome of a SCUBA dive.

Wolves, foxes, birds, caterpillars, and snails are animals, and there are some of each of them. Also there are some grains, and grains are plants. Every animal either likes to eat all plants or all animals much smaller than itself that like to eat some plants. Caterpillars and snails are much smaller than birds, which are much smaller than foxes, which in turn are much smaller than wolves. Wolves do not like to eat foxes or grains, while birds like to eat caterpillars but not snails. Caterpillars and snails like to eat some plants. Prove that there is an animal that likes to eat a grain eating animal.

The basic notion of set theory is membership of a set. Using a member/2 predicate, define set equality, intersection, union, power set, empty set, and diifference. For example, intersection is defined as:

    ! [X,A,B] :
      ( member(X,intersection(A,B))
    <=> ( member(X,A)
        & member(X,B) ) )
Now write conjectures for transitivity of subset, associativity of set intersection, and distribution of intersection over union.


Satisfiability Preserving Transformations

One of the techniques for establishing that C is a logical consequence of Ax is to show that Ax U {~C} is unsatisfiable. Thus the ability to detect that a set of formulae is unsatisfiable, is important. It may be difficult or impossible to show directly that a set is unsatisfiable. A satisfiability preserving transformation (SPT) takes a set of formulae and transforms it to a new set, such that if the original set is satisfiable then so is the transformed set. Conversely, if the transformed set is unsatisfiable then so is the original set.

If, by repetitive use, the application of SPTs produces a set that is obviously unsatisfiable (e.g., containing FALSE) from a set of formulae, then, iteratively, this means that the very original set is also unsatisfiable. If the original set is of the form Ax U {~C}, this establishes that C is a logical consequence of Ax. The process of producing a set that is obviously unsatisfiable is called finding a refutation.


Logical Inference

An inference rule infers formulae from parent formulae.

An inference rule is sound if it infers only logical consequences of its parents.

The operation of applying a sound inference rule to parents from a set, and then adding the inferred formula back into the set, is a SPT (think why!). (There are other SPTs, but this is an important one.) Thus sound inference rules form the basis of a a simple algorithm for establishing logical consequence.

The basic saturation procedure is :

While a refutation has not been found
    Copy formulae from the set
    Generate logical consequences
    Put logical consequences into the set
Note the "Copy", indicating that a formula may be used multiple times with a new set of variables each time.

An inference system is complete if, by repetitive use, it can infer every logical consequence of its input.

An inference system is refutation complete if, by repetitive use, it can infer FALSE (a contradiction) from every unsatisfiable set.

Note: A complete inference system can infer all logical consequences, while a refutation complete inference system can only check (via the unsatisfiability idea) for logical consequence.


Exercises

  1. Express the following scenarios in first-order logic, use ATP to check the axioms for satisfiability, convert them by hand to CNF, find a resolution proof by hand, find a proof using ATP.
    • Axioms: Every city has crime. USA is a country. Washington is a city. The capital of every country is a beautful city. Washington is the capital of the USA. Conjecture: Washington is beautiful but has crime.
    • Axioms: Garfield is a cat. Odie is a dog. Cats and dogs are animals. Jon is a human. Every animal has a human owner. Jon is the owner of Garfield and Odie. Garfield and Odie are the only animals that Jon owns. If a cat is chased by a dog, then the owner of the cat hates the owner of the dog. Odie has chased Garfield. Conjecture: Jon hates himself.
    • Axioms: Every student is enrolled in at least one course. Every professor teaches at least one course. Every course has at least one student enrolled. Every course has at least one professor teaching it. The coodinator of a course is a professor who is teaching it. If a student is enrolled in a course then the student is taught by every professor who teaches the course. CSC410 is a course. Michael is a student enrolled in CSC410. Victor is the coordinator of CSC410. Conjecture: Michael is taught by Victor.


Exam Style Questions

  1. What are the two major limitations of propositional logic?
  2. What are the three components of a 1st order logic language?
  3. What is important about closed formulae?
  4. Translate the following into 1st order logic:
    Suming, Yi, and Yury are students, and are the only three students. If a student works hard then they get a good grade. At least one of the students works hard. Therefore at least one student will get a good grade.
  5. Express the following scenario and conclusion in 1st order logic.
    There are some students who fail. If a student fails, then either there is a lecturer who has taught the student badly, or the student is stupid. No lecturer teaches any student badly. Therefore there is some student who is stupid.
  6. Explain why truth tables cannot be used to establish logical consequence in lst order logic.
  7. What does it mean for an inference system to be {sound, complete, refutation complete}? Which of these properties are desireable in a refutation based ATP system?
  8. Explain how unsatisfiability can be used to establish logical consequence in classical logic.